(x+2)(x+1)=x^2+5

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Solution for (x+2)(x+1)=x^2+5 equation: 


Simplifying
(x + 2)(x + 1) = x2 + 5

Reorder the terms:
(2 + x)(x + 1) = x2 + 5

Reorder the terms:
(2 + x)(1 + x) = x2 + 5

Multiply (2 + x) * (1 + x)
(2(1 + x) + x(1 + x)) = x2 + 5
((1 * 2 + x * 2) + x(1 + x)) = x2 + 5
((2 + 2x) + x(1 + x)) = x2 + 5
(2 + 2x + (1 * x + x * x)) = x2 + 5
(2 + 2x + (1x + x2)) = x2 + 5

Combine like terms: 2x + 1x = 3x
(2 + 3x + x2) = x2 + 5

Reorder the terms:
2 + 3x + x2 = 5 + x2

Add '-1x2' to each side of the equation.
2 + 3x + x2 + -1x2 = 5 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
2 + 3x + 0 = 5 + x2 + -1x2
2 + 3x = 5 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
2 + 3x = 5 + 0
2 + 3x = 5

Solving
2 + 3x = 5

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 3x = 5 + -2

Combine like terms: 2 + -2 = 0
0 + 3x = 5 + -2
3x = 5 + -2

Combine like terms: 5 + -2 = 3
3x = 3

Divide each side by '3'.
x = 1

Simplifying
x = 1

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